What is the probability that 3 customers waiting in a bank will be served in the sequence of their arrival at the bank
In an A.P. the first term is 2, and the sum of the 1st and the 6th term is 16\(\frac{1}{2}\). What is the 4th term
Simplify 125\(^{\frac{-1}{3}}\) x 49\(^{\frac{-1}{2}}\) x 10\(^0\)
