What is the probability that 3 customers waiting in a bank will be served in the sequence of their arrival at the bank
Probability that 3 customers are attended to in the sequence they arrive
= prob of attending to the 1st arrival x prob of attending to the second last x prob of attending to the last
= \(\frac{1}{3} \times \frac{1}{2} \times \frac{1}{1}\)
= \(\frac{1}{6}\)
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