(a) Define the following terms as applied to a convex mirror:

(i) principal focus; (ii) pole (iii) radius of curvature.

(b) State one advantage and one disadvantage of using a convex mirror as a driving mirror.

(c) Draw a clearly labelled diagram to illustrate how two converging lenses may be arranged to form a compound microscope.

(d) An object 2.5 mm long is viewed through a converging lens of focal length 10.0 cm held close to the eye. A magnified image of the object is formed 30.0 cm from the lens. Calculate the:

(i) distance of the object from the lens; (ii) size of the image; (iii) power of the lens.

 (a) Define: (i) reactance; (ii) impedance.

(b)(i) Explain resonant frequency of an RLC circuit.

(ii) Explain the statement — the power supply voltage of a source is 230V

(c) A source of e.m.f 240V and frequency 50 Hz is connected to a series arrangement of a resistor, an inductor and a capacitor. When the current in the capacitor is 10A, the potential difference across the resistor is 140 V and that across the inductor is 50 V. Calculate the:

(i) potential difference across the capacitor (ii) capacitance of the capacitor; (iii) inductance of the indicator.

(d) Draw and label one vector diagram for the potential differences across the inductor, the capacitor and the resistor in (c) above.

(a) Explain: (i) nuclear fission; (ii) nuclear fusion.

(b)(i) State three applications of atomic energy.

(ii) Define State. life.

(iii) Give the expression that relates the halflife, T, and the decay constant, X, of a radioactive material.

(c) A radioactive element X with atomic number 88 and mass number 226 emits in succession:

(i) an alpha particle, (ii) a beta particle and (iii) gamma radiation. Explain, using equations where necessary, the changes that take place in the atomic structure of the element at each stage.

 A ball thrown vertically upward reaches a maximum height of 50 m above the level of projection. Calculate the;

(i) time taken to reach the maximum height,

(ii) speed of the throw. [g = 10 ms\(^{-2}\)]

A lead shot is projected from the ground level with a velocity u at an angle \(\theta\) to the horizontal. Given the time, t for the lead shot to reach its maximum height as; t = \(\frac{u \sin \theta}{g}\) where "g" is the acceleration of free fall due to gravity, show that the greatest height reached by the body is h\(_{\text{max}} = \frac{u^2 \sin^2 \theta}{2g}\)