Evaluate Log\(_2\) 8√2
Given that log\(_3\) 27 = 2x + 1, find the value of x.
Find the value of y, if log (y + 8) + log (y - 8) = 2log 3 + 2log 5
Solve the logarithmic equation: \(log_2 (6 - x) = 3 - log_2 x\)
Solve: \(log_3 x + log_3 (x - 8) = 2\)
