Solve the quadratic inequalities x\(^2\) - 5x + 6 ≥ 0
Determine the value of x for which (x\(^2\) - 1) > 0?
Given that x = -\(\frac{1}{2}\) and y = 4 evaluate 3x\(^2y+xy^2\)
Factorize a2x - b2y - b2x + a2y
Solve the following equation \(\frac{2}{2r - 1}\) - \(\frac{5}{3}\) = \(\frac{1}{r + 2}\)
