If the diagram is the graph of y = x\(^2\), the shaded area is
Integrate (2x+1)\(^3\)
Evaluate \(\int_0^1 4x - 6\sqrt[3] {x^2}dx\)
Integrate y = 4x\(^3\) + 2x + cos x.
Integrate the function y = 3x\(^2\) + 2x - 5 with respect to x.