In the diagram above, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of ΔQPT
In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
Evaluate, using logarithm tables \(\frac{5.34 \times 67.4}{2.7}\)
