The nth term of a sequence is given by (-1)\(^{n-2}\) x 2\(^{n-1}\). Find the sum of the second and third terms.

Simplify: \(\frac{4^{-\frac{1}{2}} \times 16^{\frac{3}{4}}}{4^{\frac{1}{2}}}\)

Simplify: \(\frac{\log \sqrt{27}}{\log {81}}\)

Factorize the expression 2s\(^2\) - 3st - 2t\(^2\).

Solve the equation x\(^2\) - 2x - 3 = 0