If log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 0.4771, simplify: (Log\(_{10}\)8-log\(_{10}\)2) ÷ (Log\(_{10}\)9 - log\(_{10}\)2)
Find the value of t such that the expression \(\frac{1}{t}\) + \(\frac{4}{3}\) - \(\frac{5}{6t}\) + 1 is equal to zero