Assuming loge 4.4 = 1.4816 and loge 7.7 = 2.0142, then the value of loge \(\frac{7}{4}\) is
Simplify \(\frac{(a - \frac{1}{a}) (a^{\frac{4}{3}} + \frac{1}{a^{\frac{2}{3}}})}{a^2 - (\frac{1}{a})^2}\)
If x\(^4\) - kx\(^3\) + 10x\(^2\) + lx - 3 is divisible by (x - 1), and if when it is divided by (x + 2) the remainder is 27, find the constants k and l