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Mathematics JAMB Past Questions

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1076
The solution of the quadratic equation px2 + qx + b = 0 is
  • A. \(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
  • B. \(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
  • C. \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
  • D. \(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)
View Answer & Discuss (4) JAMB 1988
1077

Simplify \(\frac{1}{x^2 + 5x + 6}\) + \(\frac{1}{x^2 + 3x + 2}\)

  • A. \(\frac{x}{(x +2)(x - 3)}\)
  • B. \(\frac{2}{(x + 5)(x - 3)}\)
  • C. \(\frac{2}{(x + 1)(x + 3)}\)
  • D. \(\frac{2}{(x - 1)(x - 3)}\)
View Answer & Discuss (5) JAMB 1988
1078

Simplify \(\frac{4a^2 - 49b^2}{2a^2 - 5ab - 7b^2}\)

  • A. \(\frac{a - b}{2a + b}\)
  • B. \(\frac{2a + 7b}{a - b}\)
  • C. \(\frac{2a - 7b}{a + b}\)
  • D. \(\frac{2a + 7b}{a + b}\)
View Answer & Discuss (11) JAMB 1988
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1079

If cot \(\theta\) = \(\frac{x}{y}\), find cosec\(\theta\)

  • A. \(\frac{1}{y}\)(x2 + y2)
  • B. \(\frac{x}{y}\)
  • C. \(\frac{1}{y}\)\(\sqrt{x^2 + y^2}\)
  • D. \(\frac{x - y}{y}\)
View Answer & Discuss (1) JAMB 1988
1080
In triangle PQR, PQ = 1cm, QR = 2cm and PQR = 120o Find the longest side of the triangle
  • A. \(\sqrt{3}\)cm
  • B. \(\sqrt{7}\)cm
  • C. 3cm
  • D. 7cm
View Answer & Discuss JAMB 1988
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts