Simplify \(\sqrt[3]{\frac{27a^{-9}}{8}}\).
PQR is the diameter of a semicircle RSP with centre at Q and radius of length 3.5cm. If QPT = 60º. Find the perimeter of the figure PTRS. \(\pi\) = \(\frac{22}{7}\)
In a triangle PQT, QR = \(\sqrt{3}cm\), PR = 3cm, PQ = \(2\sqrt{3}\)cm and PQR = 30o. Find angles P and R