Ethane burns completely in oxygen according to the equation below; C2H6(g) + 7/2 O2(g) →...

Ethane burns completely in oxygen according to the equation below; C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(g)
What is the amount in moles of carbon (IV) oxide will be produced when 6.0g of ethane are completely burnt in oxygen.?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

Answers (4)

Explanation:
Balanced Eqn
2C2H6 + 7O2 = 4CO2 + 6H2O
By the Balanced eqn
60g ethane requires 7x32= 224g oxygen
here ethane is in excess.oxygen will be fully consumed
hence
300g oxygen will consume
60 ⋅ = 80.36g ethane
leaving (270-80.36)= 189.64 g ethane.
By the Balanced eqn 60g ethane produces 4x44 g CO2
hence amount of CO2 produced =
4 ⋅ 44 ⋅ = 235.72g
and its no. of moles will be =5.36
where 44 is the molar mass of Carbon
dioxide
Sydneystudio
1 month ago
Molar mass of ethane = 2*12+6*1=30g/mol
. amount of ethane = 6/30=0.2mol . since
the mol ratio of ethane to carbon(iv)oxide is
equal to 1:2, then amount of CO2= 2*0.2 =
0.4mol .
Sean frost
1 month ago
Balanced Eqn
2C2H6 + 7O2 = 4CO2 + 6H2O
By the Balanced eqn
60g ethane requires 7x32= 224g oxygen
here ethane is in excess.oxygen will be fully
consumed
hence
300g oxygen will consume
60 ⋅ = 80.36g ethane
leaving (270-80.36)= 189.64 g ethane.
By the Balanced eqn 60g ethane produces 4x44
g CO2
hence amount of CO2 produced =
4 ⋅ 44 ⋅ = 235.72g
and its no. of moles will be =5.36
where 44 is the molar mass of Carbon
dioxide
Like 0 Dislike 0 Qu
Ask Your Own Question

Quick Questions

See More School-Based Questions Questions