At Around 150keV, if you know that the Mass Attenuation Coefficient of lead is around 4 cm2/g, and that its density is 11.34 g/cm3:
a) What is the Half-Value Layer (HVL) of lead at this photon energy?
b) How many sheets of HVL thickness you need to use in order to attenuate the X-Ray beam at around 150 keV to be lower than 10−3 of its incident.?
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Asked by saidi on 26th April, 2024
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