How much heat is required to convert 20 g of ice at 0°C to water at the same temperature? [Specific latent heat of ice = 336 Jg\(^{-1}\)]
The heat required to convert ice at 0°C to water at the same temperature is given by the formula: Q = m × L,
where m is the mass of the ice, and L is the specific latent heat of ice.
Substituting the given values, we get Q = 20 g × 336 Jg\(^{-1}\) = 6.72 × 10\(^3\) J.
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