(b)i. Explain Ohmic conductor:
ii. Explain resistivity of the material of a wire.
1. v\(_{o}\) = 3.0v
2. V\(_{R}\) = 0.20 volts
3. l = 0.20, 1\(^{-1}\) = \(\frac{1}{1} = \frac{1}{0.2}\) = 5
V = 0.2, V\(^{-1}\) = \(\frac{1}{V} =\frac{1}{0.2}\) = 5
Table of values/observations
S/N | IA | I\(^{-1}\)(A\(^{-1}\)) | V(volts) | V\(^{-1}\)(volts\(^{-1}\)) |
1 | 0.20 | 5.00 | 0.19 | 5.26 |
2 | 0.25 | 4.00 | 0.23 | 4.35 |
3 | 0.30 | 3.33 | 0.28 | 3.57 |
4 | 0.35 | 2.86 | 0.33 | 3.03 |
5 | 0.40 | 2.50 | 0..38 | 2.63 |
Slope (s) = \(\frac{\bigtriangleup {V}^{-1}}{\bigtriangleup {I}^{-1}}\)
S = \(\frac{5.1-1.0}{4.55-12} = \frac{4.1}{3.35}\) = 1.224
S\(^{-1}\) = \(\frac{1}{s} = \frac{1}{1.224}\) = 0.817
N.B: R = S\(^{-1}\) = 1.0
Precautions taken to ensure accurate results are as follows
(b)i. An ohmic conductor is s Conductor in which the current passing through it is proportional to the p.d across the conductor, provided temperature and other physical conditions are constant.
ii. The resistivity of the material of a wire is the resistance of a unit length of the wire of unit Crofs sectional area. It is denoted by p. and measured in ohm-metre (L-m).
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}