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2007 WAEC Physics Practical You have been provided with an accumulator E, a standard resistor Rx, two resistance boxes...

Physics
WAEC 2007

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You have been provided with an accumulator E, a standard resistor Rx, two resistance boxes RB\(_{1}\) and RB\(_{2}\), two keys K\(_{1}\) and K\(_{2}\) and other necessary apparatus.

  1. Measure and record the e.m.f of the accumulator.
  2. Connect a circuit as shown above.
  3. Set the resistance R, in the resistance box such that R in RB\(_{1}\) = R in RB\(_{2}\) = 1\(\Omega\).
  4. With K\(_{1}\) open and K\(_{2}\) closed, measure and record the potential difference V across the standard resistor Rx. (v) Close K, and K,. Read and record the potential difference V\(_{o}\) across Rx.
  5. Evaluate V\(_{1}^{-1}\)
  6. Repeat procedure (v) for four other values of R = 2, 3, 4 and 5\(\Omega\) respectively. In each case, ensure that the value of R in RB\(_{1}\) is equal to the value of R in RB\(_{2}\).
  7. Evaluate V\(_{1}^{-1}\) in each case. Tabulate your readings.
  8. Plot a graph of V\(_{1}^{-1}\) on the vertical axis against R on the horizontal axis starting both axes from the origin (0,0).
  9. Determine the slope, s, of the graph and the intercept on the vertical axis.
  10. Evaluate y = \(\frac{1}{s}\)
  11.  State two precautions taken to ensure accurate results

(b)i. Explain what is meant by the potential difference between two points in an electric circuit

ii. A cell has an e.m.f. of 3 V. When it is connected across a resistor of resistance 4\(\Omega\), a current 0.5A passes through the circuit. Calculate the internal resistance of the cell.

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Explanation

Table of values (Observation)

R (\(\Omega\) V\(_{1}\)(v) V\(_{1}^{-1}\)
1 1.50 0.667
2 1.30 0.769
3 1.15 0.870
4 1.10 0.909
5 0.90 1.111

 

Slope (s) = \(\frac{\bigtriangleup {V}_{1}^{-1}}{DR} = \frac{1.22 - 0.6}{6.5 - 0.3}\)

= \(\frac{0.62}{6.20}\) = 0.1

Intercept (c) = 0.57

Evaluation: y = \(\frac{1}{S} = \frac{1}{0.1}\) = 10


Precautions:

  • I removed the key when not taking readings
  • I ensured tight connections/clean terminals
  • I avoided parallax error in reading the voltmeter
  • I corrected for zero error on the voltmeter

(b)i. The potential difference (pd) (in volts) between two points in a circuit is the work done (in joules) when one unit of positive charge (coulomb) moves from one point to the other

ii. E = IR + Ir, 3 =0.5 x 4 + 0.5r, 3 = 2 +0.5r

r = \(\frac{3 - 2}{0.5}\) = 2\(\Omega\)


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WAEC offline past questions - with all answers and explanations in one app - Download for free
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts