Physics
WAEC 2015
Two angles of a pentagon are in the ratio 2:3. The others are 60
o each. Calculate the smaller of the two angles
-
A.
72o
-
B.
100o
-
C.
120o
-
D.
144o
Correct Answer: Option D
Explanation
The diagram given simple illustrates that a pentagon contains three \(\Delta\)s.
Two angles which are in the ratio 2:3 will have actual values 2x
o, 3x
o respectively. Thus 2x
o + 3x
o + 3 x 60 = 3x sum of angles of \(\Delta\)a
i.e. 5x
o + 180
o = 3 x 180
o
5x
o + 180
o = 540
o
5x
o = 540
o - 180
o
5x
o = 360
o
x
o = \(\frac{360^o}{5}\)
= 72
o
Hence, the smaller of the two angles is
2 x 72
o = 144
o
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