Physics
JAMB 2007
If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600µc across the field is
-
A.
0.8j
-
B.
1.8j
-
C.
9.0j
-
D.
18.0j
Correct Answer: Option B
Explanation
Workdone = product of the charge Q, and the p.d V.
i.e Work done = QV
= 600 * 10
-6 *2.1 * 10
3
=1.8j
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