Physics
WAEC 2014
an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms
-1]
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A.
104.4m
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B.
207.9m
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C.
415.8m
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D.
523.8m
Correct Answer: Option B
Explanation
S = \(\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9\)
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