Physics
WAEC 2013
The work function of a metal is 2.56 x 10
-19J. Calculate the frequency of a photon whose energy is required to eject from the metal an electron with kinetic energy of 3.0ev. [1 eV = 1.6 x 10
-19J, h = 6.6 x 10
-34Js]
-
A.
5.56 x 1019Hz
-
B.
1.66 x 1019Hz
-
C.
1.12 x 1015Hz
-
D.
8.42 x 1014Hz
Correct Answer: Option C
Explanation
F = \(\frac{K.E + Wo}{h}\)
= \(\frac{3.0 \times 1.6 \times 10^{-19} + 2.56 \times 106{-19}}{6.6 \times 106{-34}}\)
- 1.12 x 10-15HZ
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