Correct Answer: Option A

Explanation

XL = \(2\pi f L\)

= = 2 x 3.142 x 50 x 0.12

= 37.68\(\Omega\)

Z = \(\sqrt{R^2 + X_L^2} = \sqrt{4^2 + 37.68^2}\)

I = \(\frac{V}{z} = \frac{240}{37.89}\)

= 6.3A

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