Physics
WAEC 2011
A metal of mass 200g at a temperature of 100
oC is placed in 100g of water at 25
oC in a container of negligible heat capacity. If the final steady temperature is 30
oC, calculate the specific heat capacity of the metal. [specific heat capacity of the water is 4200 Jkg
-1 K
-1]
-
A.
150 Jkg-1K-1
-
B.
300 Jkg-1K-1
-
C.
320 Jkg-1K-1
-
D.
1960 Jkg-1K-1
Correct Answer: Option A
Explanation
MC\(\theta\)metal = MC\(\theta _{water}\)
0.2 x C x 70 = 0.1 x 4200 x 5
C = 150
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