Physics
WAEC 2010
simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms
-1 at the centre of the oscillation
-
A.
125\(\pi\)
-
B.
25.00\(\pi\)
-
C.
100.00 \(\pi\)
-
D.
400.00\(\pi\)
Correct Answer: Option B
Explanation
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}