Physics
WAEC 2005
A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
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A.
1.2C
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B.
3.3C
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C.
3330.0C
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D.
12.0000.0C
Correct Answer: Option A
Explanation
Q = CV
= 600 x 10-6 x 200 = 1.2C
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