Physics
WAEC 2004
A machine of velocity ratio 5 is used in lifting a load with an effort of 500N. If the machine is 80% efficient. Determine the magnitude of load
-
A.
2500N
-
B.
2000N
-
C.
900N
-
D.
625N
Correct Answer: Option B
Explanation
M.A = \(\frac{Eff \times V.r}{100} = \frac{80 \times 5}{100} = 4\)
Load = effort x M.A
= 4 x 500 = 2000N
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}