Physics
WAEC 2003
A lamp is rated 240V 60W, calculate the resistance of its filament
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A.
240\(\Omega\)
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B.
360\(\Omega\)
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C.
960\(\Omega\)
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D.
1440\(\Omega\)
Correct Answer: Option C
Explanation
R = \(\frac{V^2}{P} = \frac{240^2}{60} = 960\Omega\)
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