Physics
WAEC 2002
Three capacitors each of capacitance 18\(\mu F\) are connected in series. Calculate the effective capacitance of the capacitors
-
A.
54.00\(\mu F\)
-
B.
18.00\(\mu F\)
-
C.
6.00\(\mu F\)
-
D.
0.17\(\mu F\)
Correct Answer: Option C
Explanation
\(\frac{1}{c} = \frac{1}{18} + \frac{1}{18} + \frac{1}{18} = \frac{3}{18}\)
c = 6\(\mu F\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}