Physics
WAEC 1998
Calculate the resistance of the filament of lamp rated at 240V 60W
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A.
240\(\Omega\)
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B.
360\(\Omega\)
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C.
960\(\Omega\)
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D.
144\(\Omega\)
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E.
2880\(\Omega\)
Correct Answer: Option C
Explanation
P = \(\frac{V^2}{R} = \frac{240^2}{60} = 960\)
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