Physics
JAMB 1978
The latent heat of fusion of ice is 80cal g
-1. How much heat is required to change 10g of ice at Q
oC into water at the same temperature?
-
A.
80 cal
-
B.
10 cal
-
C.
8 cal
-
D.
800 cal
-
E.
400 cal
Correct Answer: Option D
Explanation
Quantity of heat = ml
= 10 x 80
= 800 cal
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