Correct Answer: Option B

Explanation

212°F ... 100°C

\(\theta\)°F ... 20°C

32°F ... 0°C

\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)

180 = 5(\(\theta\) - 32)

5\(\theta\) = 180 + 160 = 340

\(\theta\) = 68°F

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