a calorimeter of thermal capacity 80j contains 20g of water at 25oC. Water at 100oC...

JAMB 1980

a calorimeter of thermal capacity 80j contains 20g of water at 25^oC. Water at 100^oC is added so that the final temperature of the set-ups is 50^oC. The amount of water added is (Heat capacity of water = 4.18J/g/^oC)

A. 20g
B. 25g
C. 45g
D. 50g
E. 100g

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Correct Answer: Option A

Explanation

Heat lost = heat gained

mc\(\theta\) = c\(\theta\) + mc\(\theta\)

m x 4.18 x (100 - 50) = 80(50 -25) + [20 x 4.18] x (50 - 25)

m = 20g

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a calorimeter of thermal capacity 80j contains 20g of water at 25oC. Water at 100oC...

Correct Answer: Option A

Explanation

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