Eight alpha decays and six beta decays are necessary before an atom of 2 \(^{238}_{92}U\)...

JAMB 1989

Eight alpha decays and six beta decays are necessary before an atom of 2 \(^{238}_{92}U\) achieves stability. The final product in the chain has an atomic number of

A. 70
B. 78
C. 82
D. 90

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Correct Answer: Option C

Explanation

U \(\to\) 8(\(^{4}_{2}He\)) + 6(\(^{0}_{-1}e\)) + \(^{b}_{a}X\)

92 = (8 X 2) + (6 X -1) + a

a = 82

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Eight alpha decays and six beta decays are necessary before an atom of 2 \(^{238}_{92}U\)...

Correct Answer: Option C

Explanation

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