Physics
JAMB 1989
A piece of wood of mass 40g and uniform cross-sectional area of 2cm
2 floats upright in water. The length of the wood immersed is
-
A.
30cm
-
B.
40cm
-
C.
20cm
-
D.
2cm
Correct Answer: Option C
Explanation
Mw displaced = 40g
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm
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