Physics
JAMB 1989
Two points on a velocity time-graph have coordinates (5s, 10ms
-1) and (20s, 20ms
-1). Calculate the mean acceleration between the two points
-
A.
0.67ms-1
-
B.
0.83ms-1
-
C.
1.50ms-1
-
D.
2.00ms-1
Correct Answer: Option A
Explanation
a = \(\frac{v - u}{\Delta t}\)
a = \(\frac{20 - 10}{20 - 5}\)
a = 0.67ms-1
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