Physics
JAMB 1990
An object which is 3cm high is placed vertically 10cm in front of a concave mirror. If this object produces an image 40cm from the mirror, the height of the image is
-
A.
0.75cm
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B.
4.00cm
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C.
8.00cm
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D.
12.00cm
Correct Answer: Option D
Explanation
\(\frac{\text {object height}}{\text{image height}}\) = \(\frac{\text {object distance}}{\text{image distance}}\)
\(\frac{3}{\text{image height}}\) = \(\frac{10}{40}\)
Image height = 12cm
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