A trough 12.0cm deep is filled with water of refractive index \(\frac{4}{3}\). By how much...

JAMB 1991

A trough 12.0cm deep is filled with water of refractive index \(\frac{4}{3}\). By how much would a coin at the bottom of the trough appear to be displaced when viewed vertically from above the water surface?

A. 3.0cm
B. 6.0cm
C. 9.0cm
D. 16.0cm

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Correct Answer: Option A

Explanation

\(\frac{4}{3}\) = \(\frac{12}{\text {Apparent depth}}\)

Apparent depth = 9cm

Height by which coin is raised = 12 - 9

= 3cm

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A trough 12.0cm deep is filled with water of refractive index \(\frac{4}{3}\). By how much...

Correct Answer: Option A

Explanation

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