Correct Answer: Option D

Explanation

\(^{27}_{13}Al\) + \(^{1}_{0}n\) \(\Rightarrow\) \(^{24}_{11}Na\) + \(^{b}_{a}X\)

a + 11 = 0 + 13 \(\Rightarrow\) a = 2

b + 24 = 1 + 27 \(\Rightarrow\) b = 4

\(^{b}_{a}X\) = \(^{4}_{2}\alpha\)

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