Correct Answer: Option C

Explanation

100^oC .... 5.5

\(\theta\)^oC .... 5.3

0^oC .... 5.0

\(\frac{\theta - 0}{100 - 0}\) = \(\frac{5.5 - 5 .0}{5.5 - 5.0}\)

\(\theta\) = 40^oC

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