Physics
JAMB 1995
The energy contained in a wire when it extended by 0.02m by a force 500 N is
-
A.
5J
-
B.
10J
-
C.
103J
-
D.
104
Correct Answer: Option A
Explanation
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}