Physics
JAMB 1997
A load of 20N on a wire of cross-sectional area 8 x 10
-7m
2, produces an extension of 10m
2. calculate Young's modulus for the material of the wire if its length is 3m
-
A.
7.0 x 1011Nm-2
-
B.
7.5 x 1011Nm-2
-
C.
8.5 x 1011Nm-2
-
D.
9.0 x 1011Nm-2
Correct Answer: Option B
Explanation
Young's modulus = \(\frac{F}{A}\) \(\div\) \(\frac{e}{L}\)
= \(\frac{20}{8 \times 10^{-7}}\) \(\div\) \(\frac{10^{-4}}{3}\)
= 7.5 x 1011Nm-2
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