Physics
JAMB 1998
How many grams of water at 17
oC must be added to 42g of ice at 0
oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 10
5Jkg
-1, specific heat capacity of water = 4200Jkg
-1k
-1]
-
A.
200g
-
B.
300g
-
C.
320g
-
D.
400g
Correct Answer: Option A
Explanation
Heat lost = Heat gained
mc\(\theta\) = mL
m x 4200 x 17 = 42 x 3.4 x 105
therefore, m = 200g
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