Correct Answer: Option D

Explanation

F \(\alpha \frac{1}{r^2}\)

therefore, \(\frac{F_1}{F_2}\) = \(\frac{r_1}{(r_2)^2}\)

\(\frac{10^{-4}}{F_2}\) = \(\frac{(0.06)^2}{(0.18)^2}\)

F = 9 x 10^-4N

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