Correct Answer: Option A

Explanation

A 300Ω resistor is connected to it in parallel

Let R\(_t\)  = total resistance in parallel

\(\frac{1}{R_t}\) = \(\frac{1}{R_1}\) + \(\frac{1}{R_2}\) = \(\frac{1}{200}\) + \(\frac{1}{300}\)

R\(_t\)  = \(\frac{200 \times 300}{200 + 300}\) = \(\frac{6000}{500}\) = 120 \(\Omega\)

There is an explanation video available below.

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