Physics
JAMB 2014
A force of 500N
1 is applied to a steel wire of cross-sectional area 0.2m
2, The tensile stress is
-
A.
2.5x104Nm-2
-
B.
1.0x102Nm-2
-
C.
1.0x103Nm-2
-
D.
2.5x103Nm-2
Correct Answer: Option D
Explanation
\(Stress = \frac{Force}{Area}\)
\(Stress = \frac{500}{0.2} = 2500\)
= 2.5 x 10
3Nm
-3
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