Physics
WAEC 1997
An atom radiates 1.5 x \(10^{-19}\)J of energy when an electron jumps from one energy level to another. What is the wavelength of the emitted radiation? (Planck’s constant =6.6 x \(10^{-34}\)Js. Speed of light in air=3 x \(10^{8}ms^{-1}\)
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A.
1.32 x \(10^{-6}\)m
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B.
2.98 x \(10^{-6}\)m
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C.
3.32 x \(10^{-6}\)m
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D.
6.82 x \(10^{-6}\)m
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E.
8.01 x \(10^{-6}\)m
Correct Answer: Option A
Explanation
\(E=\lambda v=\frac{hc}{\lambda}\Rightarrow\lambda=\frac{hc}{E}={6.6 \times10^{-34}\times3\times10^8}{1.5\times10^{-19}}\\=1.32\times10^{-6}\)
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