Physics
WAEC 1997
In a nuclear reaction, the mass defect is 2 x \(10^{-6}\)g. Calculate the energy released given that the velocity of light is 3 x \(10^{8}ms^{-1}\)
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A.
9 x \(10^{7}\)J
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B.
1.8 x \(10^{8}\)J
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C.
1.8 x \(10^{9}\)J
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D.
9 x \(10^{-10}\)J
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E.
3.6 x \(10^{11}\)J
Correct Answer: Option B
Explanation
E=\(mc^2 = 2\times10^{-6} \times10^{-3}\times(3\times10^{8})^2=1.8\times10^{8}\)
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