Physics
WAEC 1994
A battery of e.m.f 10V an internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
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A.
8.75V
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B.
7.50V
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C.
5V
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D.
2.50V
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E.
1.25V
Correct Answer: Option B
Explanation
V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V
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