Physics
WAEC 1996
A body of mass 4.2kg moving with velocity 10ms
-1 due east, hits a stationary body of mass 2.8kg. If they stick together after collision and move with velocity V due east, calculate the value of V
-
A.
3ms-1
-
B.
6ms-1
-
C.
7ms-1
-
D.
15ms-1
-
E.
17ms-1
Correct Answer: Option B
Explanation
M
1U = (M
1 + M
2)V = 4.2 x 10 = (4.2 = 2.8)V
∴ V =
4.2 x 10/7.0
= 6m/s
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}