Physics
JAMB 1978
A man walks 1km due east and then 1km due north. His displacement is
-
A.
1 km N15oE
-
B.
1 km N30oE
-
C.
\(\sqrt 2\)km N 45oE
-
D.
\(\sqrt 2\)km N 60oE
-
E.
2km N 75oE
Correct Answer: Option C
Explanation
R = \(\sqrt{1^2 + 1^2}\) = \(\sqrt{2km}\)
\(\theta\) = tan-1 \(\frac{(1)}{1}\) = 45oC
= \(\sqrt 2\)km N 45oE
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